4(y^2-60)=-49y

Solution for 4(y^2-60)=-49y equation:

4(y^2-60)=-49y

We move all terms to the left:

4(y^2-60)-(-49y)=0

We multiply parentheses

4y^2-(-49y)-240=0

We get rid of parentheses

4y^2+49y-240=0

a = 4; b = 49; c = -240;
Δ = b2-4ac
Δ = 492-4·4·(-240)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-79}{2*4}=\frac{-128}{8}
=-16
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+79}{2*4}=\frac{30}{8}
=3+3/4
$